Difference between revisions of "Worksheets/Week6"
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=== Part 1 === | === Part 1 === | ||
Case study: Achieve a stability value of 50 days or more, for a new product. We had a full factorial set of experiments in 3 factors: | |||
* B: feed concentration: -1 == 5%; +1 == 15% | * B: feed concentration: -1 == 5%; +1 == 15% | ||
* C: mixer type: -1 = R mixer; +1 = W mixer | * C: mixer type: -1 = R mixer; +1 = W mixer | ||
{| class="wikitable" | |||
! Factor name | |||
! Description | |||
! Low value | |||
! High value | |||
! Type of factor | |||
|- | |||
| '''A''' | |||
| Enzyme strength | |||
| 20% | |||
| 30% | |||
| Numeric factor | |||
|- | |||
| | |||
| | |||
| | |||
| | |||
| | |||
|- | |||
| | |||
| | |||
| | |||
| | |||
| | |||
|} | |||
A: enzyme strength [numeric factor] | |||
B: feed concentration [numeric factor] | |||
C: mixer type [categorical factor] | |||
y = Stability [days] | |||
In this notebook we will show what we loose out if we pretend we only did half the experiments. In other words, we actually have 8 experiments, but we will see what happens if we only use 4 of them. | |||
<html><div data-datacamp-exercise data-lang="r" data-height="auto"> | <html><div data-datacamp-exercise data-lang="r" data-height="auto"> | ||
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# This is the half-fraction, when C = A*B | # This is the half-fraction, when C = A*B | ||
A | A = c(-1, +1, -1, +1) | ||
B | B = c(-1, -1, +1, +1) | ||
C | C = A * B | ||
# The response: stability [units=days] | # The response: stability [units=days] | ||
y | y = ... | ||
model_stability_poshalf | |||
model_stability_poshalf = lm(y ~ A*B*C) | |||
summary( | summary(model_stability_poshalf) | ||
# Uncomment this line if you run the code in RStudio | # Uncomment this line if you run the code in RStudio | ||
Line 26: | Line 66: | ||
source('https://yint.org/paretoPlot.R') | source('https://yint.org/paretoPlot.R') | ||
source('https://yint.org/contourPlot.R') | source('https://yint.org/contourPlot.R') | ||
paretoPlot( | paretoPlot(model_stability_poshalf) | ||
# This is the other half-fraction, when C = -A*B | # This is the other half-fraction, when C = -A*B | ||
A | A = c(-1, +1, -1, +1) | ||
B | B = c(-1, -1, +1, +1) | ||
C | C = -1 * A * B | ||
# The response: stability [units=days] | # The response: stability [units=days] | ||
y | y = ... | ||
model_stability_neghalf = lm(y ~ A*B*C) | |||
summary( | summary(model_stability_neghalf) | ||
</code> | </code> |
Revision as of 09:00, 17 October 2019
Part 1
Case study: Achieve a stability value of 50 days or more, for a new product. We had a full factorial set of experiments in 3 factors:
- B: feed concentration: -1 == 5%; +1 == 15%
- C: mixer type: -1 = R mixer; +1 = W mixer
Factor name | Description | Low value | High value | Type of factor |
---|---|---|---|---|
A | Enzyme strength | 20% | 30% | Numeric factor |
A: enzyme strength [numeric factor] B: feed concentration [numeric factor] C: mixer type [categorical factor] y = Stability [days]
In this notebook we will show what we loose out if we pretend we only did half the experiments. In other words, we actually have 8 experiments, but we will see what happens if we only use 4 of them.
# This is the half-fraction, when C = A*B
A = c(-1, +1, -1, +1)
B = c(-1, -1, +1, +1)
C = A * B
# The response: stability [units=days]
y = ...
model_stability_poshalf
model_stability_poshalf = lm(y ~ A*B*C)
summary(model_stability_poshalf)
# Uncomment this line if you run the code in RStudio
#library(pid)
# Comment these 2 lines if you run this code in RStudio
source('https://yint.org/paretoPlot.R')
source('https://yint.org/contourPlot.R')
paretoPlot(model_stability_poshalf)
# This is the other half-fraction, when C = -A*B
A = c(-1, +1, -1, +1)
B = c(-1, -1, +1, +1)
C = -1 * A * B
# The response: stability [units=days]
y = ...
model_stability_neghalf = lm(y ~ A*B*C)
summary(model_stability_neghalf)
Part 2
Data from a bioreactor experiment is available, were we were investigating four factors:
- A = feed rate: 5 g/min or 8 g/min
- B = initial inoculate amount: 300 g or 400 g
- C = feed substrate concentration: 40 g/L or 60 g/L
- D = dissolved oxygen set-point: 4 mg/L or 5 mg/L
The 16 experiments from a full factorial, 24, were randomly run, and the yields, y, the outcome variable were given in standard order: [60, 59, 63, 61, 69, 61, 94, 93, 56, 63, 70, 65, 44, 45, 78, 77]
base <- c(-1, +1)
design <- expand.grid(A=base, B=base, C=base)
A <- design$A
B <- design$B
C <- design$C
D <- A * B * C
# Confirm that you can find these 8 runs yourself:
y <- c(60, 63, 70, 61, 44, 61, 94, 77)
model.bio <- lm(y ~ A*B*C*D)
summary(model.bio)
# Uncomment this line if you run the code in RStudio
#library(pid)
# Comment these 2 lines if you run this code in RStudio
source('https://yint.org/paretoPlot.R')
source('https://yint.org/contourPlot.R')
paretoPlot(model.bio)