Difference between revisions of "Worksheets/Week4"

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Line 106: Line 106:
#contourPlot(model.stability, 'A', 'B')
#contourPlot(model.stability, 'A', 'B')
#contourPlot(model.stability, 'A', 'C')
#contourPlot(model.stability, 'A', 'C')
# Make a prediction with this model:
xA = 0
xB = 0
xC = 0
y.hat <- predict(model.stability, data.frame(A = xA, B = xB, C = xC))
paste0('Predicted stability is: ', y.hat, ' days.')
     </code>
     </code>
</div></html>
</div></html>

Revision as of 09:20, 18 March 2019

Part 1

Your family runs a small business selling products online. The first factor of interest is whether to provide free shipping over €30 or over €50. The second factor is whether or not the purchaser must first create a profile before completing the transaction. The purchaser can still complete their transaction without creating a profile. Below are the data collected, showing the 8 experiments.


Part 2

Continuing with the case above:

Part 3

Your group is developing a new product, but have been struggling to get the product’s stability, measured in days, to the level required. You are aiming for a stability value of 50 days or more.